Find Duplicate Number/lletcode/gfg/codechef

 1. Find the Duplicate Number

Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.

There is only one repeated number in nums, return this repeated number.

You must solve the problem without modifying the array nums and uses only constant extra space.

 

Example 1:

Input: nums = [1,3,4,2,2]
Output: 2

Example 2:

Input: nums = [3,1,3,4,2]
Output: 3
Solution
class Solution {
public:
    int findDuplicate(vector<int>& nums) {
      sort(nums.begin(),nums.end());
        for(int i=1;i<nums.size();i++){
            if(nums[i]==nums[i-1]){
                return nums[i];
            }
        }
        return -1;
    }
};

Comments

Post a Comment

Popular posts from this blog

Coding Ninjas

  Given a NxM matrix containing Uppercase English Alphabets only. Your task is to tell if there is a path in the given matrix which makes the sentence “CODINGNINJA” . There is a path from any cell to all its neighbouring cells. For a particular cell, neighbouring cells are those cells that share an edge or a corner with the cell. Input Format : The first line of input contains two space separated integers N and M, where N is number of rows and M is the number of columns in the matrix. Each of the following N lines contain M characters. Please note that characters are not space separated. Output Format : Print 1 if there is a path which makes the sentence “CODINGNINJA” else print 0. Constraints : 1 <= N <= 1000 1 <= M <= 1000 Time Limit: 1 second Sample Input 1: 2 11 CXDXNXNXNXA XOXIXGXIXJX Sample Output 1: 1 bool hasPath ( vector < vector < char >> & board , int n , int m ) { // Write your code here. } #include < iostream > #include <
Read more

Code : Get Path - BFS

  Given an undirected graph G(V, E) and two vertices v1 and v2 (as integers), find and print the path from v1 to v2 (if exists). Print nothing if there is no path between v1 and v2. Find the path using BFS and print the shortest path available. Note: 1. V is the number of vertices present in graph G and vertices are numbered from 0 to V-1. 2. E is the number of edges present in graph G. 3. Print the path in reverse order. That is, print v2 first, then intermediate vertices and v1 at last. 4. Save the input graph in Adjacency Matrix. Input Format : The first line of input contains two integers, that denote the value of V and E. Each of the following E lines contains two integers, that denote that there exists an edge between vertex a and b. The following line contain two integers, that denote the value of v1 and v2. Output Format : Print the path from v1 to v2 in reverse order. Constraints : 2 <= V <= 1000 1 <= E <= (V * (V - 1)) / 2 0 <= a <= V - 1 0 <= b <= V
Read more

Code : All connected components

  Given an undirected graph G(V,E), find and print all the connected components of the given graph G. Note: 1. V is the number of vertices present in graph G and vertices are numbered from 0 to V-1. 2. E is the number of edges present in graph G. 3. You need to take input in main and create a function which should return all the connected components. And then print them in the main, not inside function. Print different components in new line. And each component should be printed in increasing order (separated by space). Order of different components doesn't matter. Input Format : The first line of input contains two integers, that denote the value of V and E. Each of the following E lines contains two space separated integers, that denote that there exists an edge between vertex a and b. Output Format : Print different components in new line. And each component should be printed in increasing order of vertices (separated by space). Order of different components doesn't matter.
Read more